Any way to get the first few characters of filename in DOS batch file Programming

Wednesday, 20 June 2018

I am using this in my program

for %%I in (*.txt) do (

The filename is in %%I.

Now i want to separate the first 2 chracters, next 3 characters, separately.

Is this possible in DOS or Cmd.exe?

Answer

set first2=%%I:~0,2% && set next3=%%I:~3,3%

I think.. geez, its been a while!

Notes