How do I detect the number of parameters to a batch file and loop through them?

Is there an easy way to detect the number of parameters passed as arguments to a batch file, and then use for /L to loop through them?

Answer

How do I detect the number of parameters to a batch file and loop through them?

%* in a batch script refers to all the arguments (e.g. %1 %2 %3 %4 %5 ...%255)

You can use %* to retrieve all of the command line arguments to a batch file.

To count the arguments and loop with for /L see the StackOverflow answer Batch-Script - Iterate through arguments by aacini:

@echo off
setlocal enabledelayedexpansion

set argCount=0
for %%x in (%*) do (
   set /A argCount+=1
   set "argVec[!argCount!]=%%~x"
)

echo Number of processed arguments: %argCount%

for /L %%i in (1,1,%argCount%) do echo %%i- "!argVec[%%i]!"

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