I have the following output from find command for finding files containing yyy in name:
./plonetheme/xxx/yyy-logo.png
./plonetheme/xxx/profiles/default/plonetheme.yyy_various.txt
./plonetheme/xxx/skins/plonetheme_yyy_custom_images
./plonetheme/xxx/skins/plonetheme_yyy_custom_images/CONTENT.txt
./plonetheme/xxx/skins/plonetheme_yyy_custom_templates
./plonetheme/xxx/skins/plonetheme_yyy_custom_templates/CONTENT.txt
./plonetheme/xxx/skins/plonetheme_yyy_custom_templates/main_template.pt
./plonetheme/xxx/skins/plonetheme_yyy_styles
./plonetheme/xxx/skins/plonetheme_yyy_styles/base_properties.props
./plonetheme/xxx/skins/plonetheme_yyy_styles/CONTENT.txt
How I would rename all file so that string yyy is replaced with zzz?
Answer
You can use bash string manipulation to achieve what you want:
find PATH/PATTERN -exec bash -c 'mv "$0" "${0/yyy/zzz}"' {} \;
The -exec switch executes the command up to the escaped ;, where {} is the path of ther file that's currently handled.
bash -c 'mv "$0" "${0/cix/stix}"' {} passes that path as an argument to bash, which moves $0 (the first argument, e.g., ./plonetheme/xxx/yyy-logo.png) to ${0/yyy/zzz} (the first manipulated argument, e.g., ./plonetheme/xxx/zzz-logo.png).
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